h^2-12h+23=0

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Solution for h^2-12h+23=0 equation:


Simplifying
h2 + -12h + 23 = 0

Reorder the terms:
23 + -12h + h2 = 0

Solving
23 + -12h + h2 = 0

Solving for variable 'h'.

Begin completing the square.

Move the constant term to the right:

Add '-23' to each side of the equation.
23 + -12h + -23 + h2 = 0 + -23

Reorder the terms:
23 + -23 + -12h + h2 = 0 + -23

Combine like terms: 23 + -23 = 0
0 + -12h + h2 = 0 + -23
-12h + h2 = 0 + -23

Combine like terms: 0 + -23 = -23
-12h + h2 = -23

The h term is -12h.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12h + 36 + h2 = -23 + 36

Reorder the terms:
36 + -12h + h2 = -23 + 36

Combine like terms: -23 + 36 = 13
36 + -12h + h2 = 13

Factor a perfect square on the left side:
(h + -6)(h + -6) = 13

Calculate the square root of the right side: 3.605551275

Break this problem into two subproblems by setting 
(h + -6) equal to 3.605551275 and -3.605551275.

Subproblem 1

h + -6 = 3.605551275 Simplifying h + -6 = 3.605551275 Reorder the terms: -6 + h = 3.605551275 Solving -6 + h = 3.605551275 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + h = 3.605551275 + 6 Combine like terms: -6 + 6 = 0 0 + h = 3.605551275 + 6 h = 3.605551275 + 6 Combine like terms: 3.605551275 + 6 = 9.605551275 h = 9.605551275 Simplifying h = 9.605551275

Subproblem 2

h + -6 = -3.605551275 Simplifying h + -6 = -3.605551275 Reorder the terms: -6 + h = -3.605551275 Solving -6 + h = -3.605551275 Solving for variable 'h'. Move all terms containing h to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + h = -3.605551275 + 6 Combine like terms: -6 + 6 = 0 0 + h = -3.605551275 + 6 h = -3.605551275 + 6 Combine like terms: -3.605551275 + 6 = 2.394448725 h = 2.394448725 Simplifying h = 2.394448725

Solution

The solution to the problem is based on the solutions from the subproblems. h = {9.605551275, 2.394448725}

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